
Apple Magic Keyboard for iPad Air 13‑inch (M4) - Swedish - Black
Compared with · Apple Magic Keyboard for iPad Air 11‑inch (M4) - Swedish - Black
- Programmable keysNot verified → Not verified
- WidthNot verified → Not verified
No stated difference in the compared specifications.
Same: Layout Swedish · Switches scissor mechanism with 1mm travel
Compare side by sideFull comparison vs Apple Magic Keyboard for iPad Air 11‑inch (M4) - Swedish - Black
More details & evidence
Exact model: UK MGYY4S/A · Magic Keyboard for iPad Air 13‑inch (M4) - Swedish - Black
Sources: 10 of 12 specifications cited.
Evidence · Some facts need verification
10/12 listed facts sourced. Checked date unavailable. This describes source coverage, not product quality or independent testing.
- Manufacturer facts
- 10
- Calculated from sources
- 0
- Independent measurements
- Not available
- Owner evidence
- Not available
- Conflicting facts
- None recorded
UK exact model
Market details
UK specification. UK availability not verified.
The specification region comes from this product’s reviewed variant record. It does not confirm local stock, warranty or delivery.
Check the manufacturer sourceWe have no current verified retailer listing for this exact variant in United Kingdom. A price you enter does not establish retailer availability.
Before you choose
- Compatibility and charging or interface features retain their manufacturer conditions. Unlisted facts remain unknown; no retailer price or stock is established.Apple UK — Magic Keyboard for iPad Air 13‑inch (M4) - Swedish - Black
Key specification sources
Evidence & conditions
Manufacturer specification
Language from the exact selected-part title. ANSI/ISO geometry, keycap legends and key count are not inferred from a language name.
Apple UK — Magic Keyboard for iPad Air 13‑inch (M4) - Swedish - BlackEvidence & conditions
Manufacturer specification
Apple UK — Magic Keyboard for iPad Air 13‑inch (M4) - Swedish - BlackEnter a price you found
Your total including delivery and taxes, for this exact variant in new condition. This remains your assumption.






